SUBJECT:
Number Theory.
TOPIC: Proportions.
LESSON:
Applying proportions to solve mathematical problems.
PREVIOUS
KNOWLEDGE: Students can solve questions involving ratios.
LESSON
OBJECTIVES: By the end of the lesson, students should be able to do the following: Define a
proportion, differentiate between direct and indirect proportions, Solve
exercises on direct and indirect proportions, and apply know of solving
problems here to solve other problems in life.
TEACHING AIDS:
Chalk, blackboard,
TEACHING
METHODS: Demonstration, questioning,
group discussion, assignment.
CLASS LEVEL:
Form Two
DURATION: 45
minutes
DATE:
INTRODUCTION
If m: 2=8:m.
Calculate the positive value of m.
Solution
m: 2 = 8:m
m/2=8/m
m×m=8×2
m2=16(take
the square root of both sides)
m=±4
m=4.
PRESENTATION
Definition:
When two or more ratios are equal, the equation that results is called a
proportion. For example if 2:3=4:9, the 2/3=4/9 is called a proportion. The
majority of problems where proportion is involved are usually solved by finding
the value of a unit quantity.
Two types of proportions will be treated here
namely direct and indirect proportions. In Direct proportion increase in one
quantity leads to an increase in the other and vice versa. In indirect
proportion, an increase in one quantity leads to a decrease in the other and
vice versa.
EXAMPLE 1: A man is paid 25000FRS CFA
for 10 days of work. Calculate his pay for 3days.
Solution
10days
receives 25000 FRS
3days
receives x
Considering ratios; 3days/10days=x/25000FRS.
3/10=x/25000FRS (multiply through by 25000FRS)
(3/10)25000FRS=x
7500FRS=x
Therefore,
the man’s pay in 5 days is 7500FRS.
EXAMPLE 2: Three students scored marks
in a Geography test in the ratio 2:3:4. The least score by one of them is 8.
Calculate the marks scored by the others.
Solution
Ratio; 2:3:4
Sum of
ratio: 2+3+4=9 ; sum of marks be x
Least
ratio=2 ; least mark=8
9 ------x
2 ------8
Considering
ratios
9:2=x:8
9/2=x/8
X/8=9/2
x=8(9/2)
x=36.
Total score is
36.
Marks scored
by the other two are as follows:
>by
second student; (3/9)36=12
>by third
student; (4/9)36=16.
EXAMPLE 3:
The three angles of a triangle are in the ratio 1:2:3. What are the angles of
the triangle? Name the triangle.
Solution
Let the
angles of the triangle be <X, <Y, <Z.
Ratio, 1:2:3
Sum of
ratio; 1+2+3=6. Sum of angles in any triangle, <X+<Y+<Z=1800
<X=
(1/6)1800=300
<Y= (2/6)1800=600
<Z=
(3/6)1800=900
A
right-angled triangle.
EXAMPLE 4:
If x:3=12:x, calculate the positive value of x
SOLUTION
x: 3=12: x (defines a proportion)
x/3=12/x (multiply through by x)
x2/3=12. (Multiply through by 3)
X2=36 (take the square root of both sides)
x=6.
So far, we
have been solving problems using direct proportions. The following example will
be on indirect proportions.
EXAMPLE 5:
Three men construct a fence round a building in 10 days. How long will it take five men to do the same
work?
Solution
3 men work in 10days
5 men work
in x.
3 men---10days
5 men ----x
The
proportion instead will be 3:5=x:10 not 3:5=10:x since it is indirect
proportion.
3:5=x: 10
3/5=x/10
10days (3/5)
=x
x=10days
(3/5)
x=6 days
EVALUATION
1) A
man earns $140 in 5 days. How much does he earn in 3 days?
2) When
$143 is divided among three children in the ratio of 2:4:5.What is the
difference between the largest and the smallest share?
3) A
car uses 10 liters of petrol in 75 km. How far will it go on 8 liters of
petrol?
4) It
takes 6 men to dig a hole 3 feet deep. How long will it take 10 men to dig that
same hole?
SUMMARY
>Equal
ratios are called a proportion. Example 2/3=x/5
>Proportions
are generally applied to solve mathematics, business, science, engineering,
banking etc.
CONCLUSION
1) A
man and his wife share a sum of money in
the ratio 3:2.If the sum is doubled, in what ratio must they share so the man
still receives the same amount?
2)
Nine milk bottles contain 4.5 liters of between
them. How much will 5 liters contain?
3)
Find the cost of 1km of pipe at 7pence for every
4cm.
4)
A wheel turns through 90 revolutions per minute.
How many degrees does it turn through in 1 second.
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