SIMPLE LESSON PLAN IN ALGEBRA

SUBJECT: Algebra
TOPIC     :Equations
LESSON :Linear Equations with one variable.
PREVIOUS KNOWLEDGE:students can add, subtract,multiply or divide real numbers. Students have seen and known the use of scale balance used for selling meat or fish. Students have also seen a bridge made up of two poles.
TEACHING AIDS: A mechanical scale balance , a 1kg mass and 2kg masses, a table, a chart showing a river with two poles as a bridge.
TEACHING METHODS:
-questioning method,
-demonstration method,
-assignment method.
OBJECTIVES: 1)Students can add, subtract or multiply integers. Students are expected to know and differentiate a linear equation from a linear expression.
2)Students should be able to solve linear equation using prescribed methods.
3)Students should be able to translate word problems into simple linear equations and solve the resulting equation correctly.
GRADE: 8 (form 3).
DURATION: 45 Minutes.
DATE : October 7, 2018.

INTRODUCTION:May ask questions like, -what name is given to some one who sells meat?,
- name the tools he uses to sell. One student will likely name a scale balance.
-Use the masses of 1kg and 2kg to explain how the scale balance works laying emphasis on when it is balanced.
This is preparing their minds towards solving linear equations.
-Show the picture of the bridge and ask them to tell you the significance of the bridge. This isto open up the idea of the "equal to" sign.
PRESENTATION:
-Define with examples, linear expression and linear equation. ie  2x+4, as linear expression and 2x+4=10, linear equation. Point out that an equation has the "=" sign while the expression does not."x" is called a variable or unknown quantity.
-Give examples of linear equations in one variable starting from simply to complex and solve them using two very important principles namely the ADDITION and MULTIPLICATION principles.
a) The Addition Principle; In this principle, if p=q, then p+x=q+x, and
 p-x=q-x.
 Example1.Solve
i)x+5=8
ii) y-3=7
Solution
i) x+5=8(add -5 to both sides of the equation)
x+5-5=8-5
x+0=3
x=3 answer.
ii) y-3=7(add 3 to both sides of the equation)
y-3+3=7+3
y-0=10
y=10 answer.
The Multiplication Principle.
In this principle, if p=q then p×n=q×n and p÷n=q÷n for n#0.
Example 2. Solve the equations
I) x/3=4
ii) 3x=24
  Solution
i)x/3=4(multiply both sides by 3)
x/3×3=4×3
x×1=12
x=12.Answer.
ii) 3x=24(multiply both sides by 1/3)
3x×1/3=24×1/3
x×1=8
x=8. Answer
EVALUATION: Give exercises and ask students to solve while you move round to assist those who face difficulties.
Example. Solve the following equations
1) y+4=7
2) m-3=2
3)x/3=6
4)5p=20
SUMMARY: Give a run down of all what has been taught making sure it is in line with your objectives.You may ask some questions to ensure students have understood.Let the summary be such that students get all what has been taught at a glance.
eg -linear expression; 2x+4,
    - linear equation; 2x+4=0, x is a variable.
    -solution of linear equation by the principle of ADDITION or MULTIPLICATION
CONCLUSION : Give exercises as assignment on what has been taught and two others that will lead to the next lesson.
 Assignment.
Solve the following;
1) x+4=9
2) m-3=11
3) 4y=32
4) 2x+3=7
5) 4x+-1=-9
6) (3x-2)/5=8
7) 2x+4= 3x+6
8) 2(x+5)=3x-4
  Solve these noting that questions 7and 8 will lead you the new LESSON titled "solving linear equations with the variable on both sides of the equation. TO CONTINUE FROM HERE.
  This is more of a guide to enable the teacher write out a good lesson note.